Evaluate $102^{3}$

10612118

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1611208

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1061208

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1161208

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Solution

The correct option is C $1061208$
${(102)}^{3} = {(100 + 2)}^{3} {(a + b)}^{3} = a^{3} + b^{3} + 3 a b (a + b) {(100 + 2)}^{3} = {(100)}^{3} + {(2)}^{3} + 600 (102) = 1000000 + 8 + 61200 = 1061208$

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