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Question

Evaluate 1023 (3 is power) using suitable identities


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Solution

To find 1023

We know that (a+b)3=a3+b3+3ab(a+b)

1023can be written as 100+23 which is equal to a+b3

where a=100,b=3

100+23=1003+23+3Ɨ100Ɨ2100+2100+13=1000000+8+600102=1000000+8+61200=1061208

Hence, 1023 is 1061208


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