The correct option is B 12100 110^2 = (100 + 10)^2 ⇒ (a + b)^2 = a^2 + b^2 + 2(a)(b) ⇒ (100 + 10)^2 = 100^2 + 10^2 + 2(10)(100) ⇒ (100 + 10)^2 = 10000 + 100 + ...

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Byju's Answer

Standard VIII

Mathematics

Expansion of (x+y)^2

Evaluate: 110...

Question

Evaluate: $110^{2}$

11100

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121000

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12100

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12000

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Solution

The correct option is C
12100

$110^{2} = (100 + 10)^{2}$

$\Rightarrow (a + b)^{2} = a^{2} + b^{2} + 2 (a) (b)$

$\Rightarrow (100 + 10)^{2} = 100^{2} + 10^{2} + 2 (10) (100)$

$\Rightarrow (100 + 10)^{2} = 10000 + 100 + 2000 = 12100$

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Similar questions

Find $(110)^{2}$ .

Q. The value of

(110)^{2}

is _______

Use the short cut method to find $(110)^{2}$ .

Q. Solve the binary division

{(101110)}_{2} \div {(110)}_{2}

and also find out remainder and quotient.

Q. The remainder and the quotient of the binary division

(101110)_{2} \div (110)_{2}

are respectively

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Evaluate: 1102

The correct option is C 12100 1102=(100+10)2 ⇒(a+b)2=a2+b2+2(a)(b) ⇒(100+10)2=1002+102+2(10)(100) ⇒(100+10)2=10000+100+2000=12100

Evaluate: $110^{2}$

The correct option is C
12100

$110^{2} = (100 + 10)^{2}$

$\Rightarrow (a + b)^{2} = a^{2} + b^{2} + 2 (a) (b)$

$\Rightarrow (100 + 10)^{2} = 100^{2} + 10^{2} + 2 (10) (100)$

$\Rightarrow (100 + 10)^{2} = 10000 + 100 + 2000 = 12100$