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Question

Evaluate : (12)3+73+53

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Solution

(i) It is given that
(12)3+73+53
If x+y+z=0 then x3+y3+z3=3abc
According to that
12+7+5=0
So we get
(12)3+73+53=3(12)(7)(5)
(12)3+73+53=1260

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