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Byju's Answer
Standard VI
Mathematics
Algebraic Identities
Evaluate 136 ...
Question
Evaluate
136
×
107
.
A
14552
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B
14551
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C
14562
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D
13552
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Solution
The correct option is
A
14552
136
×
107
=
(
100
+
36
)
(
100
+
7
)
Using
(
x
+
a
)
(
x
+
b
)
=
x
2
+
(
a
+
b
)
x
+
a
b
we get
(
100
+
36
)
(
100
+
7
)
=
100
2
+
(
36
+
7
)
100
+
36
×
7
=
10000
+
43
×
100
+
252
=
14552
Suggest Corrections
4
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Q.
Using suitable identity, evaluate
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Q.
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(using identities)
Q.
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Evaluate:
{
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Q.
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