Evaluate:
$14 - [21 - {28 - (14 - 1)}]$

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Solution

Using (B)racket (O)f (D)ivision (M)ultiplication (A)ddition (S)ubtraction[BODMAS] rule:

$14 - [21 - {28 - (14 - 1)}]$

$= 14 - [21 - {28 - 13}]$

$= 14 - [21 - 15]$

$= 14 - 6$

$= 8$

$14 - [21 - {28 - (14 - 3)}] = 8$

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Similar questions

\frac{6^{12} \times {(35)}^{28} \times {(15)}^{16}}{{(14)}^{12} \times {(21)}^{11}}

:

Class interval	$7 - 14$	$14 - 21$	$21 - 28$	$28 - 35$	$35 - 42$
Frequency	$2$	$4$	$3$	$10$	$1$

2.2 + 1 \frac{4}{7} - 4.5 + 2 \frac{8}{35}

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