1
Question
Evaluate: 17−[17−(17−(17−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯17−17))].
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Solution
To evaluate an expression , we must first simplify the expression below the vinculum, then inside the small bracket , then inside the curly bracket , and finally inside the square bracket using the DMAS rule,
Thus, 17−[17−(17−(17−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯17−17))]
=17−[17−(17−(17−0))]
[Removing vinculum]
=17−[17−(17−17)]
[Removing small bracket ]
=17−[17−0]
[Removing curly bracket]
=17−17
[Removing square bracket]
=0
∴ The value of 17−[17−(17−(17−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯17−17))] is 0.
Thus, 17−[17−(17−(17−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯17−17))]
=17−[17−(17−(17−0))]
[Removing vinculum]
=17−[17−(17−17)]
[Removing small bracket ]
=17−[17−0]
[Removing curly bracket]
=17−17
[Removing square bracket]
=0
∴ The value of 17−[17−(17−(17−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯17−17))] is 0.
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