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Byju's Answer
Standard XII
Chemistry
Depression in Freezing Point
Evaluate:1abc...
Question
Evaluate :
1
a
b
c
1
b
c
a
1
c
a
b
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Solution
∆
=
1
a
b
c
1
b
c
a
1
c
a
b
When
a
=
b
,
the
first
two
rows
become
identical
.
Hence
,
a
-
b
i
s
a
f
a
c
t
o
r
.
Similarly
,
when
b
=
c
and
c
=
a
,
the
second
and
third
and
third
and
first
rows
become
identical
.
Hence
,
b
-
c
and
c
-
a
are
also
factors
.
The
degree
of
product
of
the
diagonal
elements
is
3
.
Hence
,
there
are
no
other
factors
.
1
a
b
c
1
b
c
a
1
c
a
b
=
λ
(
a
-
b
)
(
b
-
c
)
(
c
-
a
)
Where
λ
is
a
constant
1
0
2
1
1
0
1
2
0
=
2
λ
Putting
a
=
0
,
b
=
1
and
c
=
2
to
find
λ
⇒
2
=
2
λ
⇒
λ
=
1
H
e
n
c
e
,
1
a
b
c
1
b
c
a
1
c
a
b
=
(
a
-
b
)
(
b
-
c
)
(
c
-
a
)
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0
Similar questions
Q.
Evaluate the following :
∣
∣ ∣
∣
1
a
b
c
1
b
c
a
1
c
a
b
∣
∣ ∣
∣
Q.
Prove that :
1
a
b
c
1
b
c
a
1
c
a
b
=
1
a
a
2
1
b
b
2
1
c
c
2
Q.
show that
∣
∣ ∣
∣
1
a
b
c
1
b
c
a
1
c
a
b
∣
∣ ∣
∣
=
(
a
−
b
)
(
b
−
c
)
(
c
−
a
)
Q.
Prove that
∣
∣ ∣
∣
1
a
b
c
1
b
c
a
1
c
a
b
∣
∣ ∣
∣
=
(
a
−
b
)
(
b
−
c
)
(
c
−
a
)
.
Q.
The determinants
∣
∣ ∣
∣
1
a
b
c
1
b
c
a
1
c
a
b
∣
∣ ∣
∣
and
∣
∣ ∣ ∣
∣
1
a
a
2
1
b
b
2
1
c
c
2
∣
∣ ∣ ∣
∣
are not identically equal.
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