Evaluate $(2 + 3 + 4)^{2}$ using identities

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Solution

The correct option is A
81

We use the identity $(a + b + c)^{2}$ = $a^{2} + b^{2} + c^{2} + 2 a b + 2 b c + 2 c a$

Replacing the value of a,b,and c with 2,3, and 4 respectively.

We get $(2 + 3 + 4)^{2}$ = $2^{2} + (3)^{2} + (4)^{2} + 12 + 24 + 16$

= $4 + 9 + 16 + 52$

= 81

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