To evaluate an expression , we must first simplify the expression below the vinculum, then inside the small bracket , then inside the curly bracket , and finally inside the square bracket using the DMAS rule,
Thus, 2−[3−(6−5−¯¯¯¯¯¯¯¯¯¯¯¯4−3)]
=2−[3−(6−(5−1))]
[Removing vinculum]
=2−[3−(6−4)]
[Removing small bracket ]
=2−[3−2]
[Removing curly bracket]
=2−1
[Removing square bracket]
=1
∴ The value of 2−[3−(6−5−¯¯¯¯¯¯¯¯¯¯¯¯4−3)] is 1.