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Byju's Answer
Standard VII
Mathematics
Zero Exponents
Evaluate:260
Question
Evaluate:
(
2
6
)
0
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Solution
Step:Finding the values using laws of exponents
Given ,
(
2
6
)
0
Now ,we know that
(
2
6
)
0
=
2
6
×
0
[
∵
(
a
m
)
n
=
a
m
n
]
=
2
0
=
1
[
∵
a
0
=
1
]
Hence,the values of
(
2
6
)
0
is
1
.
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