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Question

Evaluate:
2(cos58sin32)3(cos38cosec52tan15tan60tan75)

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Solution

2(cos58sin32)3(cos38 cosec52tan15tan60tan75)
2(sin(9058)sin32)3(sin(9038) cosec52tan15tan60tan75) sin(90θ)=cosθ
2(sin32sin32)3(sin52 cosec52cot(9015)tan60tan75) cot(90θ)=tanθ
2(sin32sin32)3(sin52 cosec52cot75tan60tan75)
23(1tan60) sinθ cosec θ=1 andcotθtanθ=1
23(13) tan60=3
21=1

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