Evaluate- 2sin230o 30o-3cos260o 230o-

2sin 30^∘30^∘ 3cos^260^∘^230^∘ =2(12)^2(√(3)) 3(12)^2(2√(3))^2 =√(3)2 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Range of Trigonometric Ratios from 0 to 90 Degrees

Evaluate: 2...

Question

Evaluate: $2 {sin}^{2} 30^{o} cot 30^{o} - 3 {cos}^{2} 60^{o} {sec}^{2} 30^{o}$ .

Open in App

Solution

$2 sin 30^{\circ} cot 30^{\circ} - 3 {cos}^{2} 60^{\circ} {sec}^{2} 30^{\circ}$
$= 2 (\frac{1}{2})^{2} (\sqrt{3}) - 3 (\frac{1}{2})^{2} (\frac{2}{\sqrt{3}})^{2}$
$= \frac{\sqrt{3}}{2} - 1$

Suggest Corrections

Similar questions

Evaluate : $\int \frac{x^{3}}{(x - 1) (x^{2} + 1)} d x .$

Evaluate $\int \frac{s i n x - x c o s x}{x (x + s i n x)}$ dx.

Q. Evaluate :

Evaluate : $\int_{0}^{π} \frac{x t a n x}{s e c x + t a n x} d x .$ OR Evaluate : $\int_{1}^{4} {|x-1|+|x-2|+|x-4|}dx.$

Evaluate: $\int_{0}^{\frac{π}{2}} \frac{s i n^{2} x}{s i n x + c o s x} d x .$

Evaluate: $\int_{- 1}^{2} (e^{3 x} + 7 x - 5) d x$ as a limit of sums.

$Evaluate : (i) (\frac{2}{- 3} \times \frac{5}{4}) + (\frac{5}{9} \times \frac{3}{- 10}) (i i) (2 \times \frac{1}{4}) - (\frac{- 18}{7} \times \frac{- 7}{15}) (i i i) (- 5 \times \frac{2}{15}) - (- 6 \times \frac{2}{9}) (i v) (\frac{8}{5} \times \frac{- 3}{2}) + (\frac{- 3}{10} \times \frac{9}{16})$

Join BYJU'S Learning Program

Evaluate: 2sin230o cot30o−3cos260o sec230o.

2sin30∘cot30∘−3cos260∘sec230∘=2(12)2(√3)−3(12)2(2√3)2=√32−1

Evaluate: $2 {sin}^{2} 30^{o} cot 30^{o} - 3 {cos}^{2} 60^{o} {sec}^{2} 30^{o}$ .

$2 sin 30^{\circ} cot 30^{\circ} - 3 {cos}^{2} 60^{\circ} {sec}^{2} 30^{\circ}$
$= 2 (\frac{1}{2})^{2} (\sqrt{3}) - 3 (\frac{1}{2})^{2} (\frac{2}{\sqrt{3}})^{2}$
$= \frac{\sqrt{3}}{2} - 1$