Evaluate $2 {tan}^{- 1} \frac{1}{5}$ .

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Solution

Now,
$2 {tan}^{- 1} \frac{1}{5}$
$= {tan}^{- 1} \frac{\frac{2}{5}}{1 - \frac{1}{25}}$
$= {tan}^{- 1} \frac{2 \times 5}{24}$
$= {tan}^{- 1} \frac{5}{12}$ .

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Similar questions

Evaluate : $t a n {2 t a n^{- 1} (\frac{1}{5}) + \frac{π}{4}} .$

t a n [2 {t a n}^{- 1} (\frac{1}{5}) - \frac{π}{4}]

2 {tan}^{- 1} (\frac{1}{5}) + {sec}^{- 1} (\frac{5 \sqrt{2}}{7}) + 2 {tan}^{- 1} (\frac{1}{8}) = \frac{π}{4} .

2 {tan}^{- 1} \frac{1}{5} + 2 {tan}^{- 1} \frac{1}{8} + {sec}^{- 1} \frac{5 \sqrt{2}}{7} = \frac{π}{4}

2 {tan}^{- 1} \frac{1}{5} + {sec}^{- 1} \frac{5 \sqrt{2}}{7} + 2 {tan}^{- 1} \frac{1}{8} = \frac{π}{4}

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