Evaluate- 2 x 2 - y 2 - 8 z 2 - 2 - 2 x y - 4 - 2 y z - 8 z x

Consider the given expression. 2x^2+y^2+8z^2 2√(2)xy+4√(2)yz 8zx ⇒ ( √(2)x+y+2√(2)z)^2 Hence, this is the answer. ...

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Evaluate: 2...

Question

Evaluate: $2 x^{2} + y^{2} + 8 z^{2} - 2 \sqrt{2} x y + 4 \sqrt{2} y z - 8 z x$

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2 x^{2} + y^{2} + 8 z^{2} - 2 \sqrt{2} x y + 4 \sqrt{2} y z - 8 z x

= (- \sqrt{2} x + y + 2 \sqrt{2} z) (- \sqrt{2} x + y + 2 \sqrt{2} z)

2 x^{2} + y^{2} + 8 z^{2} - 2 \sqrt{2} x y + 4 \sqrt{2} y z - 8 x z

2 x^{2} + y^{2} + 8 z^{2} - 2 \sqrt{2} x y + 4 \sqrt{2} y z - 8 x z

Factorise $2 x^{2} + y^{2} + 8 z^{2} - 2 \sqrt{2} x y + 4 \sqrt{2} y z - 8 x z$

Factorise:

(i)

(ii)

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