Evaluate : $2550 - [510 - {270 - (90 - ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 80 + 7)}]$

Open in App

Solution

Using BODMAS, we can simplify the given expression.
$2550 - [510 - {270 - (90 - ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 80 + 7)}]$
It can written as
$= 2550 - [510 - {270 - (90 - (80 + 7))}]$
$= 2250 - [510 - {270 - (90 - 87)}]$
$= 2550 - [510 - {270 - 3}]$
$= 2550 - [510 - 267]$
$= 2550 - 243$
$= 2307$
$∴ 2550 - [510 - {270 - (90 - ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 80 + 7)}] = 2307$

Suggest Corrections

Similar questions

2550÷[510-{270-(20-80+7)}]

Simplify each of the following:
$2550 - 510 - 270 - (90 - 80 + 70)$

\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}

\sqrt{5} = 2.236 and \sqrt{10} = 3.162

\begin{array}{rcl} \frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}} & = & \frac{15}{\sqrt{10} + 2 \sqrt{5} + 2 \sqrt{10} - \sqrt{5} - 4 \sqrt{5}} \\ = & \frac{15}{3 \sqrt{10} - 3 \sqrt{5}} = \frac{5}{\sqrt{10} - \sqrt{5}} \end{array}

sin (180^{\circ} - x) . cot (270^{\circ} + x) . tan (270^{\circ} - x) . sec (180^{\circ} + x)

Join BYJU'S Learning Program