Evaluate: (2y+5)(2y+5)
We know, (a+b)2=a2+2ab+b2 So,(2y+5)(2y+5) can also be written as (2y+5)2
=(2y)2+(2×2y×5)+52 [Here a =2y, b =5] =4y2+20y+25
Using an identity expand : (2y+5)(2y+5)
Factorise: 4y2+20y+25