Evaluate: (2y+5)(2y+5)
4y2+10y+25
4y2+20y+25
4y2+20y+15
y2+20y+25
(a+b)2=a2+2ab+b2 (2y+5)(2y+5) =(2y)2+(2)(2y)(5)+52 =4y2+20y+25
Using an identity expand : (2y+5)(2y+5)
Factorise: 4y2+20y+25