Evaluate 3/5+7/3+[-2/5]+[-2/3] after rearragement.

Open in App

Solution

Given problem is,

3/5 + 7/3 + ( - 2/ 5 ) + ( - 2 / 3 )

= 3 / 5 + ( - 2 / 5 ) + 7 /3 + ( - 2 / 3 )

[ rearranged the like fractions at one place ]

= 3 / 5 - 2 / 5 + 7 / 3 - 2 / 3 [ since + × - = - ]

= ( 3 - 2 ) / 5 + ( 7 - 2 ) /3

= 1 / 5 + 5 / 3

LCM of 5 and 3 = 5 × 3 = 15

= ( 3 + 25 ) / 15

= 28 / 15

Suggest Corrections

Similar questions

\frac{2}{5} \times \frac{- 3}{7} - \frac{3}{7} \times \frac{3}{5} - \frac{1}{14}

\frac{3}{7} + \frac{3}{5} + (\frac{- 2}{3})

\frac{1 \frac{1}{7} - \frac{2}{3} + \frac{\frac{2}{5}}{1 - \frac{1}{25}}}{1 - \frac{1}{7} ⎛ ⎜ ⎜ ⎜ ⎝ \frac{1}{3} + \frac{\frac{2}{5}}{1 - \frac{2}{5}} ⎞ ⎟ ⎟ ⎟ ⎠}

{(\frac{2}{7})}^{2} \times {(\frac{7}{2})}^{- 3} \div {{(\frac{7}{5})}^{- 2}}^{- 4}

\frac{7 + 3 \sqrt{5}}{7 - 3 \sqrt{5}} + \frac{7 - 3 \sqrt{5}}{7 + 3 \sqrt{5}} =

Join BYJU'S Learning Program