Evaluate- 35x-7-29x-11-48x-1-3-17

3(5x 7) 2(9x 11)=4 ( 8x 13) 17 or, 15x 21 18x+22=32x 43 17 or, 3x+1=32x 43 17 or, 9x+3=96x 4 51 or, 105x=58 ∴ x=58106⇒ x=2953 ...

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Byju's Answer

Standard VIII

Mathematics

Solving Equations with Variables on Both Sides

Evaluate: 35...

Question

Evaluate:
$3 (5 x - 7) - 2 (9 x - 11) = 4 (8 x - \frac{1}{3}) - 17$

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Solution

Given $3 (5 x - 7) - 2 (9 x - 11) = 4 (8 x - \frac{1}{3}) - 17$
$\Rightarrow 15 x - 21 - 18 x + 22 = 32 x - \frac{4}{3} - 17$
$\Rightarrow - 3 x + 1 = 32 x - \frac{4}{3} - 17$
$\Rightarrow - 3 x + 1 = \frac{(32 \times 3) x - 4 - (17 \times 3)}{3}$
$\Rightarrow - 9 x + 3 = 96 x - 4 - 51$
$\Rightarrow 105 x = 58$
$∴ x = \frac{58}{105}$

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Similar questions

Q. Solve:
3(5x − 7) − 2(9x − 11) = 4(8x − 13) − 17

3(5x-7)-2(9-11)=4(8x-13)-17

Pls solve my query

Q. Evaluate:

(i) \frac{3}{7} + \frac{- 4}{9} - \frac{- 11}{7} - \frac{7}{9}

(i i) \frac{2}{3} + \frac{- 4}{5} - \frac{1}{3} - \frac{2}{5}

(i i i) \frac{4}{7} - \frac{- 8}{9} - \frac{- 13}{7} + \frac{17}{9}

Q. Evaluate:

\frac{1}{3 \times 7 \times 11} + \frac{1}{7 \times 11 \times 15} + \frac{1}{11 \times 15 \times 19} + . . .

upto

20

terms.

Evaluate :

$(i) \frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5} (i i i) \frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{9} (i v) \frac{3}{8} + \frac{- 5}{12} + \frac{3}{7} + \frac{3}{12} + \frac{- 5}{8} + \frac{- 2}{7}$

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Evaluate:3(5x−7)−2(9x−11)=4(8x−13)−17

Given 3(5x−7)−2(9x−11)=4(8x−13)−17 ⇒15x−21−18x+22=32x−43−17 ⇒−3x+1=32x−43−17⇒−3x+1=(32×3)x−4−(17×3)3⇒−9x+3=96x−4−51⇒105x=58∴x=58105

Evaluate:
$3 (5 x - 7) - 2 (9 x - 11) = 4 (8 x - \frac{1}{3}) - 17$