Question

Evaluate $\sqrt{3}$ correct up to two places of decimal.

Answer 1

$$\begin{gathered} \sqrt{3}=1.732 \\ \mathrm{Therefore},\mathrm{the}\mathrm{value}\mathrm{of}\sqrt{3}\mathrm{up}\mathrm{to}\mathrm{two}\mathrm{places}\mathrm{of}\mathrm{decimal}\mathrm{is}1.73. \end{gathered}$$