Evaluate - 3- sin4 3-2 - - - sin4 3- - - - 2- sin6 -2 - - - sin6 5- - - -

We #160; have, [ 3( cos #160; #160;^ 4 α +sin #160; #160;^ 4 α #160; ) 2( cos #160; #160;^ 6 α +sin #160; #160;^ 6 α #160; ) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sign of Trigonometric Ratios in Different Quadrants

Evaluate : 3...

Question

Evaluate : $3 [{sin}^{4} (\frac{3 π}{2} - α) + {sin}^{4} (3 π + α)] - 2 [{sin}^{6} (\frac{π}{2} + α) + {sin}^{6} (5 π - α)]$ ?

Open in App

Solution

Suggest Corrections

Similar questions

$3 [s i n^{4} (\frac{3 π}{2} - α) + s i n^{4} (3 π + α)] - 2 [s i n^{6} (\frac{π}{2} + α) + s i n^{6} (5 π - α)] =$

The expression $3 [{sin}^{4} (\frac{3 π}{2} - α) + {sin}^{4} (3 π + α)] - 2 [{sin}^{6} (\frac{π}{2} + α) + {sin}^{6} (5 π + α)]$ is equal to

3 [{sin}^{4} (\frac{3 π}{2} - α) + {sin}^{4} (3 π + α)] - 2 [{sin}^{6} (\frac{π}{2} + α) + {sin}^{6} (5 π - α)]

3 [{sin}^{4} (\frac{3 π}{2} - α) + {sin}^{4} (3 π + α)] - 2 [{sin}^{6} (\frac{π}{2} + α) + {sin}^{6} (5 π - α)]

a = {sin}^{4} (\frac{3 π}{2} - α) + {sin}^{4} (3 π + α)

b = {sin}^{6} (\frac{π}{2} + α) + {sin}^{6} (5 π - α)

3 a - 2 b

Join BYJU'S Learning Program