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Question

Evaluate: 30+[(2×(25¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯133))].

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Solution

To evaluate an expression , we must first simplify the expression below the vinculum, then inside the small bracket , then inside the curly bracket , and finally inside the square bracket using the DMAS rule,

Thus, 30+[(2×(25¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯133))]
=30+[(2×(2510))]

[Removing vinculum]
=30+[(2×15)]

[Removing small bracket ]

=30+[(30)]
[Multiplication : 2×15]

=30+[30]
[Removing curly bracket]

=3030
[Removing square bracket]
=0

The value of 30+[(2×(25¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯133))] is 0.

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