Evaluate 33×27 using suitable identity.
Using Formula (x+a)(x+b) = x2+(a+b)x+ab
Writing 33 as 30+3 and 27 as 30−3
So, 33×27
=(30+3)(30−3)
=302+[3+(−3)]30+(3)(−3)
= 900+[(0)30]−9
= 891
Hence, 33×27=891