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Question

Evaluate 33×27 using suitable identity.

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Solution

Using Formula (x+a)(x+b) = x2+(a+b)x+ab

Writing 33 as 30+3 and 27 as 303

So, 33×27

=(30+3)(303)

=302+[3+(3)]30+(3)(3)

= 900+[(0)30]9

= 891

Hence, 33×27=891


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