Evaluate: (369)2–(368)2
We know that a2−b2=(a+b)(a–b)
On comparing (369)2–(368)2 with the identity, we have a = 369 and b = 368
(3692−3682) =(369+368)(369–368) =737×1 =737
Evaluate : ∫x3(x−1)(x2+1)dx.
OR
Evaluate ∫sin x−x cos xx(x+sin x) dx.