Question

Evaluate: $(3a-7b+4c{)}^2$

Answer 1

To evaluate: $(3a-7b+4c{)}^2$

Now,

$(3a-7b+4c{)}^2$

$=(3a{)}^2+(-7b{)}^2+(4c{)}^2+2(3a\left)\right(-7b)+2(-7b\left)\right(4c)+2(4c\left)\right(3a)$
$=9a^2+49b^2+16c^2-42ab-56bc+24ca$