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Question

Evaluate: (3n2−2n+5n4+3)(−6)

A
30n4+18n212n18
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B
30n418n212n18
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C
30n418n212n18
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D
30n4+18n212n18
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Solution

The correct option is B 30n418n212n18
(3n22n+5n4+3)(6)
First, multiply each term of the polynomial by the first term of the monomial.
= 6.3n2+(6).(2n)+(6).5n4+3(6)
= 18n212n30n418
= 30n418n212n18

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