Question

Evaluate $\left(3x^4{y}^2\right)\left(2x^2{y}^3\right)$ for x=1 and y=2.

Answer 1

For x=1 and y=2

$\left(3x^4{y}^2\right)\left(2x^2{y}^3\right)(3\times 1^4\times 2^2)\times (2\times 1^2\times 2^3)(3\times 1\times 4)\times (2\times 1\times 8)=12\times 16=192$