Evaluate: (3x+4y)(3x−4y)(9x2+16y2) is equal to 81x4−256y4.
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Solution
Given, (3x+4y)(3x−4y)(9x2+16y2) Applying the formula (a+b)(a−b)=a2−b2, where a=3x,b=4y (3x+4y)(3x−4y)(9x2+16y2)=(9x2−16y2)(9x2+16y2) =(9x2)2−(16y2)2 =(81x4−256y4)