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B
12x2z2−30z8+12z10
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C
12x4−30z6+12z7
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D
12x2z2−30z6+12xz7
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Solution
The correct option is D12x2z2−30z6+12xz7 −3z2(−4x2+10z4−4xz5) Multiply each term of the parenthesis by the monomial keeping the addition or subtraction sign same. =−3z2.(−4x2)+−3z2.10z4−(−3z2).4xz5 =12x2z2−30z6+12xz7