Evaluate: $4^{- 2}$ + $4^{- 1}$ + $4^{0}$ + $4^{2}$

True

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False

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\frac{257}{16}

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\frac{271}{18}

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Solution

The correct option is A
True

$4^{- 2}$ + $4^{- 1}$ + $4^{0}$ + $4^{2}$
= $\frac{1}{16}$ + $\frac{1}{4}$ + 1 +16
= $\frac{1 + 4 + 16 + 256}{16}$
= $\frac{277}{16}$

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Similar questions

4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}

= ___.

Q. Simplify :

4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}

Simplifying $4^{- 2} + 4^{- 1} + 4^{0} + 4^{2}$ gives

Evaluate :
$(i) \frac{2}{3} - \frac{4}{5} (i i) \frac{- 4}{9} - \frac{2}{- 3} (i i i) - 1 - \frac{4}{9} (i v) \frac{- 2}{7} - \frac{3}{- 14} (v) \frac{- 5}{18} - \frac{- 2}{9} (v i) \frac{5}{21} - \frac{- 13}{42}$

Evaluate $4^{4} \times 4^{- 3} \times 4^{2} \times 4^{- 5}$

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Evaluate: 4−2+4−1+40+42

The correct option is A True 4−2+ 4−1 + 40 + 42 = 116 + 14 + 1 +16 =1+4+16+25616 = 27716

Evaluate: $4^{- 2}$ + $4^{- 1}$ + $4^{0}$ + $4^{2}$

The correct option is A
True

$4^{- 2}$ + $4^{- 1}$ + $4^{0}$ + $4^{2}$
= $\frac{1}{16}$ + $\frac{1}{4}$ + 1 +16
= $\frac{1 + 4 + 16 + 256}{16}$
= $\frac{277}{16}$