(4)^2 × 2^3 ⇒ nbsp; (2^2)^2 × 2^3 ⇒ 2^4 × 2^3 nbsp; Since, (a^m)^n = nbsp;a^mn ⇒ 2^4+3 ⇒ nbsp; 2^7=128 ...

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Exponents with Unlike Bases and Same Exponent

Evaluate 42 ×...

Question

Evaluate $4^{2} \times 2^{3}$ .

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Solution

$(4)^{2} \times 2^{3}$
$\Rightarrow (2^{2})^{2} \times 2^{3}$
$\Rightarrow 2^{4} \times 2^{3}$ Since, $(a^{m})^{n}$ = $a^{m n}$
$\Rightarrow 2^{4 + 3}$
$\Rightarrow 2^{7} = 128$

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