Given ^4C_3+ ^4C_4=4!3!(4 3)!+4!4!(4 4)! #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; =4×3!3!+1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

nCr Definitions and Properties

Evaluate 4C3...

Question

Evaluate
$^{4} C_{3} +^{4} C_{4} = ?$

Open in App

Solution

Given
$^{4} C_{3} +^{4} C_{4} = \frac{4!}{3! (4 - 3)!} + \frac{4!}{4! (4 - 4)!}$

$= \frac{4 \times 3!}{3!} + 1$

$= 4 + 1$

$= 5$

Suggest Corrections

Similar questions

C_{1} + 2 C_{2} + 3 C_{3} + 4 C_{4} + . . . + n C_{n} =

C_{1} + 2 C_{2} + 3 C_{3} + 4 C_{4} + . . . . . . . . . + n + 1 n C_{n}

C_{1} + 2 C_{2} + 3 C_{3} + 4 C_{4} + . +^{n} C_{n} = n {.2}^{n - 1}

C_{0} - 2 C_{1} + 3 C_{2} - 4 C_{3} + . . . . + (- 1)^{n} (n + 1) C_{n} = 0

C_{0} +^{2} C_{1} +^{3} C_{2} +^{4} C_{3} + . . . . . . . . . . . +^{(n + 1)} C_{n}

Join BYJU'S Learning Program