Evaluate- 52 - 1221-23

Name: EXEMP - Grade 08 - Mathematics - Square-Square Root & Cube- Cube Root - Q136
Uploaded: 2022-07-04T10:36:42+05:30
Description: We have, {5^2 + (12^2)^1/2}^3 = {25 + 12}^3 =(37)^3 = 37 × 37 × 37 = 50653 ...

We have, {5^2 + (12^2)^1/2}^3 = {25 + 12}^3 =(37)^3 = 37 × 37 × 37 = 50653 ...

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Byju's Answer

Standard VIII

Mathematics

Cube Numbers

Evaluate: 52 ...

Question

Question 136

Evaluate: ${5^{2} + (12^{2})^{\frac{1}{2}}}^{3}$

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Solution

We have, ${5^{2} + (12^{2})^{\frac{1}{2}}}^{3} = {25 + 12}^{3}$
$= (37)^{3} = 37 \times 37 \times 37 = 50653$

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Similar questions

Q. Evaluate:

{(5^{2} + 12^{2})^{\frac{1}{2}}} 3

Question 136

Evaluate: ${5^{2} + (12^{2})^{\frac{1}{2}}}^{3}$

Q. Evaluate the following:
(i)

{\{(5^{2} + 12^{2})^{1 / 2}\}}^{3}

(ii)

{\{(6^{2} + 8^{2})^{1 / 2}\}}^{3}

Evaluate $136 \times 107$ .

Evaluate: ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3}$

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Cube Numbers

Standard VIII Mathematics

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Question 136 Evaluate: {52+(122)12}3

We have, {52+(122)12}3={25+12}3 =(37)3=37×37×37=50653

Question 136

Evaluate: ${5^{2} + (12^{2})^{\frac{1}{2}}}^{3}$

We have, ${5^{2} + (12^{2})^{\frac{1}{2}}}^{3} = {25 + 12}^{3}$
$= (37)^{3} = 37 \times 37 \times 37 = 50653$