Evaluate $(59)^{2}$ using the identity $(a - b)^{2} = a^{2} - 2 a b + b^{2}$

Open in App

Solution

$(59)^{2} = (60 - 1)^{2}$
$(a - b)^{2} = a^{2} - 2 a b + b^{2}$ Here $a = 60, b = 1$
$(60 - 1)^{2} = 60^{2} - (2) (60) (1) + 12 = 3600 - 120 + 1$
$59^{2} = 3481$

Suggest Corrections

Similar questions

(53)^{2}

(a + b)^{2} = a^{2} + 2 a b + b^{2}

(a - b)^{2} = a^{2} + b^{2} - 2 a b

{2.8}^{2}

209^{2}

{(a + b)}^{2} = a^{2} + 2 a b + b^{2}

\sqrt{\frac{a^{2} + 2 a b + b^{2}}{a^{2} - 2 a b + b^{2}}}

(a + b)^{2} = a^{2} + 2 a b + b^{2}

(a + 6)^{2}

Join BYJU'S Learning Program