Evaluate:
$(6^{- 1} - 8^{- 1})^{- 1} + (2^{- 1} - 3^{- 1})^{- 1}$

Open in App

Solution

$(6^{- 1} - 8^{- 1})^{1} + (2^{- 1} - 3^{- 1})^{- 1}$
${(\frac{1}{6} - \frac{1}{8})}^{- 1} + {(\frac{1}{2} - \frac{1}{3})}^{- 1}$
${(\frac{1}{24})}^{- 1} + {(\frac{1}{6})}^{- 1} = 24 + 6 = 30$ Ans

Suggest Corrections

Similar questions

\frac{8^{- 1} \times 5^{3}}{2^{- 4}}

(5^{- 1} \times 2^{- 1}) \times 6^{- 1}

8 - 8 \times \frac{2 \frac{1}{5} - 1 \frac{2}{7}}{2 - \frac{1}{6 - \frac{1}{6}}}

Evaluate: $30 - [26 - {15 + (8 - ¯ ¯¯¯¯¯¯¯¯¯¯ ¯ 6 - 3)}] \times \frac{8}{15} \div \frac{4}{9} \times \frac{3}{4} - \frac{1}{2} + 1$

Evaluate (i) (ii)

(4^{- 1} + 8^{- 1}) \div (\frac{2}{3})^{- 1}

Join BYJU'S Learning Program