Evaluate- 62 - 821-23

Name: EXEMP - Grade 08 - Mathematics - Square-Square Root & Cube- Cube Root - Q137
Uploaded: 2022-07-04T10:36:42+05:30
Description: We have, {6^2 + (8^2)^1/2}^3 = {36+8}^3 = (44)^3 = 44 × 44 × 44 = 85184. ...

We have, {6^2 + (8^2)^1/2}^3 = {36+8}^3 = (44)^3 = 44 × 44 × 44 = 85184. ...

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Byju's Answer

Standard VIII

Mathematics

Cube Numbers

Evaluate: 62 ...

Question

Evaluate: ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3}$

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Solution

We have, ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3} = {36 + 8}^{3} = (44)^{3} = 44 \times 44 \times 44 = 85184$ .

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Q. Evaluate the following:
(i)

{\{(5^{2} + 12^{2})^{1 / 2}\}}^{3}

(ii)

{\{(6^{2} + 8^{2})^{1 / 2}\}}^{3}

Question 137

Evaluate: ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3}$

Q. Evaluate:

(6^{2} + 8^{2})^{\frac{1}{2}}

Q. Evaluate

{(17^{2} - 8^{2})}^{\frac{1}{2}}

Q. Evaluate

{(17^{2} - 8^{2})}^{1 / 2}

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Cube Numbers

Standard VIII Mathematics

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Evaluate: {62+(82)12}3

We have, {62+(82)12}3={36+8}3=(44)3=44×44×44=85184.

Evaluate: ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3}$

We have, ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3} = {36 + 8}^{3} = (44)^{3} = 44 \times 44 \times 44 = 85184$ .