Question

Evaluate $6{\cos }^2{90}^{\circ }+3{\sin }^2{90}^{\circ }+4{\tan }^2{45}^{\circ }$

Answer 1

$6{\cos }^{2}90°+33{\sin }^{2}90°+4{\tan }^{2}45°$

$\Rightarrow 6\times 0+3\times 1^2+4\times 1^2=3+4=7$

Hence, the answer is $7.$