Evaluate: $7^{0} + 2^{- 1}$

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{7}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{3}{2}$
$7^{0} = \frac{7^{1}}{7^{1}} = 1$
$2^{- 1} = 2^{0 - 1} = \frac{2^{0}}{2^{1}} = 1 / 2$
$∴$ $7^{0} + 2^{- 1} = 1 + \frac{1}{2} = \frac{3}{2}$

Suggest Corrections

Similar questions

Q. Evaluate:

{(\frac{1}{4})}^{- 2} - 3 (32)^{\frac{2}{5}} \times (7)^{0} + {(\frac{9}{16})}^{- \frac{1}{2}}

5 \frac{1}{m}

, then
value of

m

Q. Evaluate

7^{0} \times (25)^{- \frac{3}{2}} - 5^{- 3}

Q. Evaluate :

7^{0} \times (25)^{- \frac{3}{2}} - 5^{- 3}

Evaluate (i) $(1^{3} + 2^{3} + 3^{3})^{\frac{1}{2}}$ (ii) ${[5 {(8^{\frac{1}{3}} + 27^{\frac{1}{3}})}^{3}]}^{\frac{1}{4}}$ (iii) $\frac{2^{0} + 7^{0}}{5^{0}}$ (iv) ${[(16)^{\frac{1}{2}}]}^{\frac{1}{2}}$

Evaluate:

\frac{{s i n}^{2} 70^{o}}{{c o s}^{2} 20^{o}} + \frac{{c s c}^{2} 20^{o}}{{s e c}^{2} 70^{o}} - 2 c o s 70^{o} c o s e c 20^{o}

Join BYJU'S Learning Program

Evaluate: 70+2−1

The correct option is C 3270=7171=1 2−1=20−1=2021=1/2 ∴ 70+2−1=1+12=32

Evaluate: $7^{0} + 2^{- 1}$

The correct option is C $\frac{3}{2}$
$7^{0} = \frac{7^{1}}{7^{1}} = 1$
$2^{- 1} = 2^{0 - 1} = \frac{2^{0}}{2^{1}} = 1 / 2$
$∴$ $7^{0} + 2^{- 1} = 1 + \frac{1}{2} = \frac{3}{2}$