Evaluate $(8.63)^{2} - (1.37)^{2}$

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Solution

We know that,
$a^{2} - b^{2} = (a + b) (a - b)$

${(8.63)}^{2} - {(1.37)}^{2}$
$= (8.63 + 1.37) (8.63 - 1.37)$
$= (10) (7.26)$
$= 72.6$

Hence, $= 72.6$

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Similar questions

Q. Find the value of:
(i) (82)² − (18)²
(ii) (128)² − (72)²
(iii) 197 × 203
(iv)

\frac{198 \times 198 - 102 \times 102}{96}

(v) (14.7 × 15.3)
(vi) (8.63)² − (1.37)²

Find the values of
(i) $(82)^{2} - (18)^{2}$
(ii) $(128)^{2} - (72)^{2}$
(iii) $197 \times 203$
(iv) $\frac{198 \times 198 - 102 \times 102}{96}$
(v) $(14.7 \times 15.3)$
(vi) $(8.63)^{2} - (1.37)^{2}$

Q. Find the value of :
(i)

(82)^{2} - (18)^{2}

(ii)

(128)^{2} - (72)^{2}

(iii)

197 \times 203

(iv)

\frac{198 \times 198 - 102 \times 102}{96}

(v)

(14.5 \times 15.3)

(vi)

(8.63)^{2} - (1.37)^{2}

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Evaluate $\int \frac{s i n x - x c o s x}{x (x + s i n x)}$ dx.

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Evaluate (8.63)2−(1.37)2

We know that,a2−b2=(a+b)(a−b)(8.63)2−(1.37)2=(8.63+1.37)(8.63−1.37)=(10)(7.26)=72.6Hence, =72.6

Evaluate $(8.63)^{2} - (1.37)^{2}$

We know that,
$a^{2} - b^{2} = (a + b) (a - b)$

${(8.63)}^{2} - {(1.37)}^{2}$
$= (8.63 + 1.37) (8.63 - 1.37)$
$= (10) (7.26)$
$= 72.6$

Hence, $= 72.6$