8149 32=498132 #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160;=729232 #160; #160; ...

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Byju's Answer

Standard VI

Mathematics

Addition and Subtraction of Decimals

Evaluate 8149...

Question

Evaluate ${(\frac{81}{49})}^{\frac{- 3}{2}}$ .

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Solution

${(\frac{81}{49})}^{\frac{- 3}{2}} = {(\frac{49}{81})}^{\frac{3}{2}} = {(\frac{7^{2}}{9^{2}})}^{\frac{3}{2}} = {[{(\frac{7}{9})}^{2}]}^{\frac{3}{2}} = {(\frac{7}{9})}^{3} = \frac{7^{3}}{9^{3}} = \frac{343}{729}$

Hence, ${(\frac{81}{49})}^{\frac{- 3}{2}} = \frac{343}{729}$ .

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Similar questions

Simplify
(i) $(\frac{81}{49})^{\frac{- 3}{2}}$
(ii) $(14641)^{0.25}$
(iii) $(\frac{32}{243})^{\frac{- 4}{5}}$
(iv) $(\frac{7776}{243})^{\frac{- 3}{5}}$

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3^{2}

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3^{2 - {log}_{3} 5}

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- 3^{2} + {(3^{2})}^{3}

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Evaluate 8149-32.

8149-32=498132 =729232 =79232 =793 =7393 =343729 Hence, 8149-32=343729.

Evaluate ${(\frac{81}{49})}^{\frac{- 3}{2}}$ .

${(\frac{81}{49})}^{\frac{- 3}{2}} = {(\frac{49}{81})}^{\frac{3}{2}} = {(\frac{7^{2}}{9^{2}})}^{\frac{3}{2}} = {[{(\frac{7}{9})}^{2}]}^{\frac{3}{2}} = {(\frac{7}{9})}^{3} = \frac{7^{3}}{9^{3}} = \frac{343}{729}$

Hence, ${(\frac{81}{49})}^{\frac{- 3}{2}} = \frac{343}{729}$ .