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Question
Evaluate (8a3−27b3) if ab=32
Evaluate (8a3−27b3) if ab=32
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Solution
The correct option is A 0
ab=32
2a=3b
2a−3b=0
(2a−3b)3=8a3−27b3−3(2a)(3b)(2a−3b)
(2a−3b)3=8a3−27b3−18ab(2a−3b)
0=8a3−27b3−18ab(0)
0=8a3−27b3
⇒8a3−27b3=0
0
ab=32
2a=3b
2a−3b=0
(2a−3b)3=8a3−27b3−3(2a)(3b)(2a−3b)
(2a−3b)3=8a3−27b3−18ab(2a−3b)
0=8a3−27b3−18ab(0)
0=8a3−27b3
⇒8a3−27b3=0
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