Evaluate $(999)^{3}$

997002999

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99700299

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998001

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97002999

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Solution

The correct option is B $997002999$
$(999)^{5} = (1000 - 1)^{3} = (1000)^{3} - 1^{3} + 3 (1000) (- 1) (999) = 997002999$

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