Evaluate $a^3$ x $3a^2$ x $-2a^7$ for $x = 1$

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Solution

The correct option is B

Given $a^{3}$ x $3 a^{2}$ x $- 2 a^{7}$ = $- 6 a^{12}$

Substitute $x = 1$

$\Rightarrow$ $- 6 a^{12}$ = $- 6 \times 1^{12}$

= $- 6$

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