evaluate:
$a + b^{2} + 2 a b (a + b)$

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Solution

$a + b^{2} + 2 a b (a + b) = a + 2 a^{2} b + b^{2} + 2 a b^{2}$

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Similar questions

∣ ∣ ∣ ∣ ∣ \begin{matrix} (b + c)^{2} & a^{2} & a^{2} b^{2} & (c + a)^{2} & b^{2} c^{2} & c^{2} & (a + b)^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ = 2 a b (a + b + c)^{3}

{(a - b)}^{2} {cos}^{2} \frac{c}{2} + {(a + b)}^{2} {sin}^{2} \frac{c}{2} = (a + b) [a + b ({sin}^{2} \frac{c}{2} - {cos}^{2} \frac{c}{2})]

\frac{\sqrt{\sin A} - \sqrt{\sin B}}{\sqrt{\sin A} + \sqrt{\sin B}} = \frac{a + b - 2 \sqrt{a b}}{a - b}

a = 3

b = - 4

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