Evaluate: $b^{2} - 9 (b - 1)^{2}$ , if b= 1.1

1.12

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1.21

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1.02

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1.11

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Solution

The correct option is B $1.12$
We substitute $b = 1.1$ in the equation $b^{2} - 9 (b - 1)^{2}$ as follows:

$b^{2} - 9 (b - 1)^{2} = (1.1)^{2} - 9 (1.1 - 1)^{2} = 1.21 - 9 (0.1)^{2} = 1.21 - (9 \times 0.01) = 1.21 - 0.09 = 1.12$

Hence, $b^{2} - 9 (b - 1)^{2} = 1.12$ if $b = 1.1$ .

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b^{2} + 5 > 9 b + 12

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