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Question

Evaluate: b2−9(b−1)2, if b= 1.1

A
1.12
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B
1.21
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C
1.02
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D
1.11
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Solution

The correct option is B 1.12
We substitute b=1.1 in the equation b29(b1)2 as follows:

b29(b1)2=(1.1)29(1.11)2=1.219(0.1)2=1.21(9×0.01)=1.210.09=1.12

Hence,b29(b1)2=1.12 if b=1.1.

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