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Question

Evaluate:
∣ ∣ ∣0xy2xz2x2y0yz2x2zzy20∣ ∣ ∣

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Solution

We have, ∣ ∣ ∣0xy2xz2x2y0yz2x2zzy20∣ ∣ ∣=x2y2z2∣ ∣0xxy0yzz0∣ ∣
[taking x2,y2 and z2 common from C1 , C2 and C3 respectively]
=x2y2z2∣ ∣00xyyyzz0∣ ∣ [C2C2C3]
=x2y2z2[x(yz+yz)]=x2y2z2.2xyz=2x3y3z3


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