Evaluate:
∣∣
∣
∣∣0xy2xz2x2y0yz2x2zzy20∣∣
∣
∣∣
We have, ∣∣
∣
∣∣0xy2xz2x2y0yz2x2zzy20∣∣
∣
∣∣=x2y2z2∣∣
∣∣0xxy0yzz0∣∣
∣∣
[taking x2,y2 and z2 common from C1 , C2 and C3 respectively]
=x2y2z2∣∣
∣∣00xy−yyzz0∣∣
∣∣ [∵C2→C2−C3]
=x2y2z2[x(yz+yz)]=x2y2z2.2xyz=2x3y3z3