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Question

Evaluate ∣ ∣1xy1x+yyx+yxy∣ ∣

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Solution

Let Δ=∣ ∣1xy1x+yyx+yxy∣ ∣
Applying R2=R2R1
Δ=∣ ∣1xy0y0x+yxy∣ ∣
Now expanding along second row
Δ=y[yy(x+y)]=y2(x+y1)

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