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Question

Evaluate:
x2x+1x1x+1x+1

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Solution

We have, x2x+1x1x+1x+1=x22x+2x10x+1 [C1C1C2]
=(x22x+2).(x+1)(x1).0=x32x2+2x+x22x+2=x3x2+2


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